40t^2-80t+40=0

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Solution for 40t^2-80t+40=0 equation: 



40t^2-80t+40=0

a = 40; b = -80; c = +40;
Δ = b2-4ac
Δ = -802-4·40·40
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{80}{80}=1$

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